Question

in what time at tap giving 60 litres of water per minute can fill a cylindrical tank of radius 3.5 M and depth 3 m

Answer 1

$volume \: \: of \: \: tank \\ = \pi \times {3.5}^{2} \times 3 = 115.5 \: {m}^{3} = 115500 \: liter \\ time \: \: required \: \: to \: \: fill \\ = \frac{115500}{60} = 1925 \: minute = 32 \: hr$

Answer 2

A cylindrical tank will be filled in 32 hours.

Step-by-step explanation:

Given:

Radius r = 3.5 m.

As 1 $m^{3}$ = 1000 lit

⇒ 1 lit = $\frac {1}{1000} m^{3}$

For 60 litres,            [given]

⇒ 60 lit = $\frac {60}{1000} m^{3}$

⇒ 60 lit = $\frac {6}{100} m^{3}$

             = $0.06 m^{3}$

Pipe delivers $0.06 m^{3}$  per minute

Volume of cylinder = π $r^2 h$

                                 = $\frac{22}{7} \times (3.5)^2 \times 3$

                                 = $\frac{22}{7} \times 12.25 \times 3$  [π = $\frac{22}{7}$]

                                 = $\frac{808.5}{7}$

                                 = 115.5 $m^3$

⇒  Pipe would fill cylinder in = $\frac{115.5}{0.06} minutes$

                                              = 1925 minutes

                                              = 32 hours (approx).