In what time will 10,000 amount to 12,100 at 10% per annum, compounded annually?
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Answer:
The required time period is two years
Step-by-step explanation:
In a situation of annually-compounded interest, we have:
A = P * (1 + R/100) ^T
In the given problem, we have:
P = 10000
A = 12100
R = 10
T = ?
12100 = 10000 * (1 + 10/100)^T
12100 = 10000 * (1.1)^T
1.21 = 1.1^T
1.1^T = 1.21
(1.1)^T = (1.1)^2 ...(Expressing 1.21 as 1.1^2)
T = 2 (Using laws of indices)
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