Question

In what time will 10000 will amount to 12100 at 10% per annum compounded annually

Answer 1

C.I.=P(1+R/100)^n

Here P = PRINCIPLE

R = RATE OF INTEREST

N = NO. OF YEAR

GIVEN:

P = 10000

C.I. =12100

R = 10%p.a.

n = ?

so put in equation

12100= 10000(1+10/100)^n

12100=10000(1+1/10)^n

12100= 10000(11/10)^n

12100/10000=(11/10)^n

121/100=(11/10)^n

(11/10)^2=(11/10)^n

as base are same of powers are:

2=n

so we have time = 2 YEARS

Answer 2

$answer$

given,

P=10000

Ci=12100

R=10%

N=?

Ci=P(1+r/100) power N

12100=10000 (1+10/100) power N

12100=10000 (1+1/10) power N

12100=10000(11/10) power N

12100/10000(11/10) power N

121/100=(11/10) power N

(11/10)²= (11/10) power N

N = 2 ans..

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