In what time will ₹1500 yield ₹496.50 as compound interest at 20%
per annum compounded semi annually?
Answers
Answer:
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Step-by-step explanation:
p = 1500
time = x
rate = 10%
amount=
p {(1 + \frac{r}{100} )}^{t}p(1+
100
r
)
t
compound interest= amount - principle=
p(1 + \frac{r}{100} {)}^{t \:} - p = 496.50p(1+
100
r
)
t
−p=496.50
= 1500(1 + \frac{10}{100 } {)}^{x} - 1500 = 496.50rs=1500(1+
100
10
)
x
−1500=496.50rs
1500( \frac{110}{100} {)}^{x} - 1500 \: = 496.501500(
100
110
)
x
−1500=496.50
1500(\frac{110}{100} {)}^{x} = 496.50 + 1500 = 1996.501500(
100
110
)
x
=496.50+1500=1996.50
( \frac{110}{100} {)}^{x} = \frac{1996.50}{1500}(
100
110
)
x
=
1500
1996.50
( \frac{110}{100} {)}^{x} = 1.331(
100
110
)
x
=1.331
( \frac{11}{10} {)}^{x} = \frac{1331}{1000}(
10
11
)
x
=
1000
1331
x = 3 because
( \frac{11}{10} {)}^{3} = \frac{1331}{1000} = 1.331(
10
11
)
3
=
1000
1331
=1.331
hope this helps you
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