Math, asked by ncpikefan, 9 months ago

in what time will 2500 amount to 3327.50 at 10% annum compound annually
plz tell fast urgent.

Answers

Answered by pandeyvinitkumar186
11

A = Rs33275

P = Rs2500O

R = 10%

SI = A-P

= = 3327525000

= Rs8275

SI = PRT/100

8275 = 25000×10×T/100 T= 8275x100/25000x10 = T= 3.3 years.

Answered by Agastya0606
2

The time in which the amount Rs.2500 becomes Rs.3327.50 will be 3 years and 3 months or 3.3 years.

Given,

Principal = Rs.2500.

Amount = Rs.3327.50.

Rate of Interest = 10% p.a.

To Find,

Time period.

Solution,

Principal(P) = Rs.2500.

Amount(A) = Rs.3327.50.

So,

Let's find simple interest using formula,

Simple Interest (S.I.) = Amount - Principal

S.I. = 3327.50 - 2500

S.I. = Rs.826.50.

Now, using the formula of S.I.

let's find the rate of interest.

S.I.=\frac{P*R*T}{100}.

Rs.826.50=\frac{2500*10*T}{100}

T = 3.3 years or 3 years and 3 months.

The time in which the amount Rs.2500 becomes Rs.3327.50 will be 3 years and 3 months or 3.3 years.

#SPJ2

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