in what time will ₹8000 yeild ₹2648 as compound interest at 10% per annum compounded yearly?
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17
Answer:
P=8000, SI=2648, A= 8000+2648 ie : 10648
R = 20%, halfyearly R = 10% , n =?
A=p(1+r/100)^n
A/P =(1+r/100)^n
(10648/8000) = (110/100)^n
(1331/1000) = (11/10)^n
[11/10]^3= [11/10]^n
By the laws of indices when bases are equal, then the powers are equal .
n=time
n =3
Mode of interest : yearly
n = 3 years.
Step-by-step explanation:
Answered by
3
Answer:
P=8000, SI=2648, A= 8000+2648 ie : 10648
R = 20%, halfyearly R = 10% , n =?
A=p(1+r/100)^n
A/P =(1+r/100)^n
(10648/8000) = (110/100)^n
(1331/1000) = (11/10)^n
[11/10]^3= [11/10]^n
By the laws of indices when bases are equal, then the powers are equal .
n=time
n =3
Mode of interest : yearly
n = 3 years.
Step-by-step explanation:
Hope it will help u!!
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