Math, asked by hypernikhil, 10 months ago

in what time will a sam of money put at 40/3% simple interest yriple itself​

Answers

Answered by venupillai
2

Answer:

15 years

Step-by-step explanation:

P = initial amount

R = rate of interest per cent per year

T = time period in years

SI = Simple interest

A = final amount

Now

SI = (P*R*T)/100

A = P + SI

We want to find T such that A = 3P when R = 40/3

=> 3P = P + SI

=> 2P = SI

=> 2P = P*R*T/100

=> 2 = R*T/100

=> R*T = 200

Now, R = 40/3

=> (40/3)*T = 200

=> T = (200*3)/40

=> T = 5*3

=> T = 15

The required time period is 15 years

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