Question

In what time will a sum be 1331 times itself at 10% rate of compound interest​

Answer 1

Principal = Rs 1000

Amount = Rs 1331

Rate = Rs. 10% p.a.

Let the time be n years then,

$= > 1000(1 + \frac{10}{100} )n = 1331$

$= > ( \frac{11}{10} )n \: = \frac{1331}{1000}$

$= > (\frac{11}{10} ) {}^{3} = \frac{1331}{1000}$

=> So, answer is 3 years.

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