In what time will a sum of money double itself at 15%per annum
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Answered by
1
Answer:
Hi ,
Let the principal = Rs p
Amount = A = 2p
Time = T years
Rate of interest = r = 15%
A = p( 1 + Tr/100 )
2p = p ( 1 + T × 15 /100 )
2p/p = ( 100 + 15T )/100
200 = 100 + 15T
200 - 100 = 15T
100 = 15T
100 / 15 = T
20 / 3 = T
Therefore ,
Required time = T = 6 2/3 years
I hope this helps you.
Step-by-step explanation:
Thank you
Answered by
1
Step-by-step explanation:
In how may years it will become 8 times ?? If the sum doubles (x2) in 15 years, then it to become 2*2*2 = 8 times as large it should double three times, so three 15 years time period are needed, which is 3*15 = 45 years. Answer: C. Bunuel wrote: A sum of money doubles itself at a compound interest in 15 years.
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