Math, asked by rajudaseril, 1 month ago

In what time will a sum of money double itself at 15%per annum​

Answers

Answered by Sanjana7530
1

Answer:

Hi ,

Let the principal = Rs p

Amount = A = 2p

Time = T years

Rate of interest = r = 15%

A = p( 1 + Tr/100 )

2p = p ( 1 + T × 15 /100 )

2p/p = ( 100 + 15T )/100

200 = 100 + 15T

200 - 100 = 15T

100 = 15T

100 / 15 = T

20 / 3 = T

Therefore ,

Required time = T = 6 2/3 years

I hope this helps you.

Step-by-step explanation:

Thank you

Answered by anamikaviju12
1

Step-by-step explanation:

In how may years it will become 8 times ?? If the sum doubles (x2) in 15 years, then it to become 2*2*2 = 8 times as large it should double three times, so three 15 years time period are needed, which is 3*15 = 45 years. Answer: C. Bunuel wrote: A sum of money doubles itself at a compound interest in 15 years.

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