In what time will a sum of money lent 8 by 3 become simple interest becomes 4 times itself
Answers
Answer:
Simple Interest I=
Simple Interest I= 100
Simple Interest I= 100PNR
Simple Interest I= 100PNR
Simple Interest I= 100PNR
Simple Interest I= 100PNR Amount A=2P
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=P
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 years
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P=
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P ⇒I=3P−P=2P
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P ⇒I=3P−P=2P So, 2P=
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P ⇒I=3P−P=2P So, 2P= 100
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P ⇒I=3P−P=2P So, 2P= 100P×N×12.5
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P ⇒I=3P−P=2P So, 2P= 100P×N×12.5
Simple Interest I= 100PNR Amount A=2P I=A−P=2P−P=PN=8 yearsSo, P= 100P×8×R ⇒R=12.5 %Now, we need to find N when A=3P ⇒I=3P−P=2P So, 2P= 100P×N×12.5
⇒N=16 years