Math, asked by zary, 1 year ago

In what time will a sum of money put at 15% simple interest triple itself?

Answers

Answered by siddhartharao77
76
Let P = a, Then A will be 3a.

We know that I = A - P

                          = 3a - a = 2a

 SI = PRT/100

 2a = a * 15 * t/100

t = (2a*100)/(a*15)

  = 40/3

  = 13.3 years. 
Answered by Cricetus
13

Given:

Rate of interest,

R = 15%

Let Principle (P) = a

then according to the question, the amount (A) will be = 3a

To find:

Time = ?

Solution:

As we know,

⇒  I=A-P

On putting the values, we get

⇒     =3a-a

⇒     =2a

Now,

⇒  SI=\frac{P\times R\times T}{100}

On substituting the given values in the above formula, we get

⇒  2a=\frac{a\times 15\times T}{100}

200=15T

⇒   T=\frac{200}{15}

⇒   T=13.3 \ years

Thus the time is "13.3 years".

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