Question

in what time will a sum of rupees 800 at 10% p. a. compounded half yearly produce an interest of rupees 126.10?​

Answer 1

CI
A = P(1+r/n ) ^nt
926.10 = 800( 1+ .1/2) ^(2t)
926.10/800 = (1.05)^2t
Take the natural log on both the sides , solve for t

Ln (1.15765) / ln (1.05) = 2t
t = 1.5 years

Answer 2

The time is 1.5 years to get interest of RS. 126.2..

Step-by-step explanation:

Since we have given that

Sum = Rs. 800

Interest = Rs. 126.10

Rate of interest = 10%

It is calculated half yearly,

Amount = Sum + Interest

$Amount=800+126.10=926.10$

So, it becomes,

$A=P(1+\dfrac{r}{n})^{nt}\\\\926.10=800(1+\dfrac{0.1}{2})^{2t}\\\\\dfrac{926.10}{800}=(1+0.05)^{2t}\\\\1.157625=(1.05)^{2t}\\\\1.05^3=1.05^{2t}\\\\3=2t\\\\t=\dfrac{3}{2}=1.5$

Hence, the time is 1.5 years to get interest of RS. 126.2..

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In what time will rupees £10,000 to Rupees 11025 at 10% compound interest compounded half yearly

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