in what time will rs 1000 amount to rs 1331 at 1% p.a
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Let the required time be n years, Then,
1331=1000\left ( 1+\frac{10}{100} \right )^{n}
=>\frac{1331}{1000}=\left ( \frac{10+1}{10} \right )^{n}
=>\left ( \frac{11}{10} \right )^{n}=\left ( \frac{11}{10} \right )^{3}
=>n=3
Hence option [B] is the right answer.
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