In what time will Rs.15625 amount to Rs. 17576 at 4% per annum Compound interest ?
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Principal=p=Rs15625
Amount =A=Rs17576
r=4%
time =n
p[(100+r)/100]^n=A
[(100+4)/100]^n=17576/15625
(104/100)^4=(26/25)^3
(26/25)^n=(26/26)^3
therefore
n=3
Amount =A=Rs17576
r=4%
time =n
p[(100+r)/100]^n=A
[(100+4)/100]^n=17576/15625
(104/100)^4=(26/25)^3
(26/25)^n=(26/26)^3
therefore
n=3
Anonymous:
check my ans surbhi
I did not understand
ab pic nahi send hogi warna send kar dete
Explain the 3rd step
104/100)^4=(26/25)^3.
is step me ?
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