In what time will rs 15625 to rs 17576 at 4% per annum compound interest?
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principal=p=Rs15625
Amount =A=Rs17576
r=4%
time =n
p[(100+r)/100]^n=A
[(100+4)/100]^n=17576/15625
(104/100)^4=(26/25)^3
(26/25)^n=(26/26)^3
therefore
n=3
Amount =A=Rs17576
r=4%
time =n
p[(100+r)/100]^n=A
[(100+4)/100]^n=17576/15625
(104/100)^4=(26/25)^3
(26/25)^n=(26/26)^3
therefore
n=3
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