In what time will Rs 2700 yield the same interest at 4% per annum as rs 2250 in 4 years at 3% per annum
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We know that
compound interest = CI = P((1+i)^n - 1)
P = Principal Amount
i = Rate of interest Per Annum
n = Time
P = 2250 ; n = 4 ; i = 3%
CI = 2250(1 + 4/100)^4 - 2250
= 2250(1 + 0.04)^4 - 2250
=2250(1.04)^4 - 2250
=2250 (1.1698) - 2250
=2632 - 2250
=382...
In what time will Rs 2700 yield the same interest at 4% per annum as rs 2250 in 4 years at 3% per annum
So P =2700 , i = 4% , n= ? , CI = 382
382 = 2700(1 + 4/100)^n - 2700
2700 + 382 = 2700 ( 1 + 0.04)^n
3082/2700 = (1 .04)^n
1.141 = (1.04)^n
(1.04)^3 = (1.04)^n
equate powers
n = 3 ; is the time taken
compound interest = CI = P((1+i)^n - 1)
P = Principal Amount
i = Rate of interest Per Annum
n = Time
P = 2250 ; n = 4 ; i = 3%
CI = 2250(1 + 4/100)^4 - 2250
= 2250(1 + 0.04)^4 - 2250
=2250(1.04)^4 - 2250
=2250 (1.1698) - 2250
=2632 - 2250
=382...
In what time will Rs 2700 yield the same interest at 4% per annum as rs 2250 in 4 years at 3% per annum
So P =2700 , i = 4% , n= ? , CI = 382
382 = 2700(1 + 4/100)^n - 2700
2700 + 382 = 2700 ( 1 + 0.04)^n
3082/2700 = (1 .04)^n
1.141 = (1.04)^n
(1.04)^3 = (1.04)^n
equate powers
n = 3 ; is the time taken
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