Question

In what time will Rs. 6880 amount to Rs. 7224, if simple interest is calculated at 10% per annum​

Answer 1

Answer:

In 0.5 year, Rs. 6880 will amount to Rs. 7224 at the rate of 10% p.a.

Step-by-step explanation:

Given sum of money = Rs. 6880

The sum will amount to = Rs. 7224

Rate of interest = 10%

Time = ??

Here:

• Principal (P) = Rs. 6880
• Amount (A) = Rs. 7224
• Rate (R) = 10%
• Time (T) = ??

$\bigstar \: \textsf{Amount = Simple Interest + Principle}$

$\rightarrow$ 7224 = SI + 6880

$\rightarrow$ SI = 7224 - 6880

$\rightarrow$ SI = 344

Simple Interest = Rs. 344

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$\bigstar \: \sf{Simple \: Interest = \: } \dfrac{Principal \times Rate \times Time}{100}$

$\sf{\rightarrow} \: 344 = \dfrac{6880 \times 10 \times T}{100}$

$\sf{\rightarrow} \: 344 = \dfrac{688 \times 1\times T}{1}$

$\sf{\rightarrow} \: 344 = 688T$

$\sf{\rightarrow} \: T = \dfrac{344}{688}$

$\sf{\rightarrow} \: T = 0.5$

Time = 0.5 year

Therefore, in 0.5 year, Rs. 6880 will amount to Rs. 7224 at the rate of 10% p.a.

Answer 2

Answer :-

• The time is 1/2 years.

To find :-

• The time in which Rs 6880 will amount to Rs 7224, if simple interest is calculated at 10% per annum.

Solution :-

• Here, the principal, amount and rate of interest is given to us. We have to find the time. For this, we first have to find the simple interest.

We know that :-

$\underline{ \boxed{\sf SI = Amount - Principal}}$

Where,

• SI = Simple Interest.

Here,

• Amount = Rs 7224.
• Principal = Rs 6880.

Hence,

$\boxed{ \bf SI = 7224 - 6880}$

$\boxed{\bf SI = Rs \: 344}$

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• Now, as we know the simple interest, let's find the time!

We know that :-

$\underline{ \boxed{ \sf SI = \dfrac{Principal \times Rate \times Time}{100}}}$

Where,

• SI = Simple Interest.

Here,

• Simple interest = Rs 344.
• Principal = Rs 6880.
• Rate = 10% per annum.

• Let the time be "t" years.

Substituting the given values in this formula,

$\longmapsto\tt 344 = \dfrac{6880 \times 10 \times t}{100}$

$\longmapsto\tt344 = \dfrac{68800 \times t}{100}$

$\longmapsto\tt344 = \dfrac{68800t}{100}$

$\longmapsto\tt344 \times 100 = 68800t$

$\longmapsto\tt34400 = 68800t$

$\longmapsto\tt \dfrac{34400}{68800} = t$

$\longmapsto \tt \cancel{\dfrac{344}{688}} = t$

$\longmapsto\overline{ \boxed{\tt \dfrac{1}{2} = t}}$

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• Hence, the time is 1/2 years.