Question

in what time will rs 6880 amount to rs 7224, if simple interset is calculated at 10% per annum

Answer 1

Answer:

$\sf \: Time \: = \frac{1}{2} year$

Step-by-step explanation:

$\rm \underline \blue{Given : }$

• Principal = P = 6880
• Amount = A = 7224
• Rate = 10%

$\rm \underline{ \blue{To \:Find : }}$

• Simple interest amount
• Time (T)

$\rm \underline{ \blue {Solution : - }}$

First we have to find simple interest

$\rm \: \: \: \: \red {\boxed{ \tt \: simple \: interest \: amount \: = A mount - principal}}$

$\sf \: : \implies simple \: interest = 7224 - 6880$

$\sf : \implies \: simple \: interest = \:Rs.344$

Now finding time then formula is

$: \implies\red{\underline{ \boxed{ \sf \:Time = \frac{Simple interest × 100}{Principal × Rate} }}}$

$\sf: \implies \: Time = \frac{ \cancel{344 }\times 1 \cancel0 \cancel0}{ \cancel{688} \cancel0 \times 1 \cancel0}$

$\boxed{ \sf: \implies \: Time = \frac{1}{2} \: years}$

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---: More information :---

• Simple interest = principal × Rate × Time / 100
• Amount = principal ( 1 + Rate /100)^n