Question

In what time will Rs68800amount Rs7224, if simple interest is calculated at 10%per annum?​

Answer 1

Correct Question :-

In what time will Rs. 6880 amount Rs. 7224, if simple interest is calculated at 10% per annum?

Answer :-

Given :-

• Amount = Rs. 7224
• Principal = Rs. 6880
• Rate of interest = 10%

To Find :-

• Time (T)

Solution :-

We know that,

Simple interest = Amount - Principal

➩ SI = 7224 - 6880

➩ SI = 344

Simple interest = Rs. 344

So, now we have

• SI = Rs. 344
• P = Rs. 6880
• R = 10%

Substituting the value in formula :-

➩ $\sf SI = \frac{PRT}{100}$

➩ $\sf 344 = \frac{ 688\cancel0 \times 1\cancel0 \times T }{1\cancel0\cancel0}$

➩ $\sf 344 = 688T$

➩ $\sf T = \frac{344}{688}$

➩ $\sf T = \frac{1}{2}$

In 0.5 years Rs. 6880 will amount Rs.7224 at the rate of 10% per annum.

Answer 2

${ \bf{ \underbrace{Correct \: question :}}}$

In what time will Rs 6880 Amount Rs7224, if simple interest is calculated at 10% per annum?

${ \bf{ \underbrace {Given :}}}$

• Principal (P) = 7224
• Amount (A) = 6880
• Rate of interest = 10%

${ \bf{ \underbrace{To \: find :}}}$

• Time ?

${ \bf{ \underbrace{Required \: Solution :}}}$

◆ We know that,

↦ Simple interest = Amount - Principal

Now substitute the values :-

↦ SI =. 7224 - 6880

↦ SI = 344

■ Hence, Simple interest Is ₹344.

◆ We also know that,

↦ SI = P × R × T / 100

Now substitute the values :-

↦ 344 = 6880 × 10 × T / 100

↦ 344 = 68800 × T / 100

↦ 344 = 688 × T

↦ T = 344 / 688

↦ T = 0.5 years