In what time will rupees 1000 amount to rupees 1210 at 10 percent per annum compounded annually through the simple interest formula? Fastest answer with full step will be marked brainliest.
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amount=principle(1 +rt/100)
1210=1000(1+10t/100)
121/100=1+t/10
21/100=t/10
2.1years=t
by compound interest
amount=p(1 +r/100)^n
1210=1000(1+r/100)^n
121/100=(1+10/100)^n
(11/10)^2=(11/10)^n
n=2years
1210=1000(1+10t/100)
121/100=1+t/10
21/100=t/10
2.1years=t
by compound interest
amount=p(1 +r/100)^n
1210=1000(1+r/100)^n
121/100=(1+10/100)^n
(11/10)^2=(11/10)^n
n=2years
themonotonuspan:
In si it's 2.1 and compound it's 2. which is correct?
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