Question

in what time will rupees 8000 amount to rupees 8360 at 6% per annum simple interest​

Answer 1

Answer:

Given :

• A sum of Rs 8000 amount to Rs 8360 at 6% per annum simple interest.

To Find :-

• What is the time period.

Solution :-

First, we have to find the simple interest :

Given :

• Principal = Rs 8000
• Amount = Rs 8360

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{\pink{Simple\: Interest =\: A - P}}}$

$\implies \sf Simple\: Interest =\: Rs\: 8360 - Rs\: 8000$

$\implies \sf\bold{\purple{Simple\: Interest =\: Rs\: 360}}$

Now, we have to find the time period :

Given :

• Principal = Rs 8000
• Rate of Interest = 6% per annum
• Simple Interest = Rs 360

According to the question by using the formula we get,

$\implies \sf\boxed{\bold{\pink{T =\: \dfrac{S.I \times 100}{P \times r}}}}$

$\implies \sf T =\: \dfrac{360 \times 100}{8000 \times 6}$

$\implies \sf T =\: \dfrac{36\cancel{000}}{48\cancel{000}}$

$\implies \sf T =\: \dfrac{36}{48}$

$\implies \bf T =\: \dfrac{3}{4}\: years$

Now, we have to convert the time into months :

$\implies \sf T =\: \bigg(\dfrac{3}{4} \times 12\bigg)\: months$

$\implies \sf T =\: \dfrac{\cancel{36}}{\cancel{4}}\: months$

$\implies \sf\bold{\red{T =\: 9\: months}}$

$\therefore$ The time period is 9 months .

Answer 2

As per given in the equation the data given as follows

$\text { Given:- } \mathrm{P}=\text { Rs. } 8000, \mathrm{~A}=\text { Rs. } 8368, \mathrm{R}=6 \%$

as we know that

$\begin{array}{l}\text { Amount }=\text { Principal }(1+((\text { Rate } \times \text { time }) / 100)) \\=(8360 / 8000)=1+((6 \times \mathrm{t}) / 100)\end{array}$

$\begin{array}{l}=(8360 / 8000)-1=((6 \times \mathrm{t}) / 100) \\=\mathrm{t}=[(8360-8000) / 8000] \times(100 / 6)\end{array}$

now

$\begin{array}{l}=(360 / 8000) \times(100 / 6) \\=(6 / 8) \times 12 \text { months } \\=9 \text { months }\end{array}$

so finally we concluded that it requires 9 months for the said question.