Question

In what time will the simple interest on ₹7560 be ₹1102.50 at 25/4 % per annum

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hello Friend}}}$

Here is your answer

P = Rs 7560
SI = Rs 1102.50
T = ?
R = 25/4%p.a

As we know the formula
T = SI x 100 /Px R
$= \frac{1102.50 \times 100 }{7560 \times \frac{25}{4} } \\ = \frac{1102.50 \times 4}{1890} \\ = \frac{7}{3} \\ = 2 \frac{1}{3} years \\ = 2 \: years \: 4 \: months$
Hope it helps you

Answer 2

Answer:

To get the simple interest time taken is 2 years 4 months.

Step-by-step explanation:

• Simple interest: If the principal is p, the rate of interest is r% per annum, then after t years the amount of simple interest will be = $\frac{prt}{100}$

• Calculation: The initial amount was = ₹7560 = the principal (p)

      Suppose Simple interest = ₹1102.5 after 't' years.

      Rate of interest = r = $\frac{25}{4}$%

      From the formula of simple interest, ₹1102.5 =  $\frac{prt}{100}$

                                                                 $\frac{7560 \times \frac{25}{4} t}{100}$ = 1102.5

                                                               7560 ×  $\frac{25}{4}$t = 1102.5 × 100

                                                               t = $\frac{1102.5 \times 100 \times 4 }{7560 \times 25}$ = $\frac{7}{3}$ years

      $\frac{7}{3}$ years = $2\frac{1}{3}$ years = 2 years + $\frac{1}{3}$ years = 2 years +( $\frac{1}{3}\times 12$ )months

                                                                    = 2 years 4 months.

     ∴ To get the simple interest time taken is 2 years 4 months.

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