Question

In what volume ratio of 0.36M HNO3 solution
should be mixed with another 0.15M HNO₃
solution to obtain 0.24 M HNO₃ solution?
​

Answer 1

we have to find the volume ratio, if 0.36 M HNO₃ solution is mixed with another 0.15 M HNO₃ solution to obtain 0.24 M HNO₃ solution.

solution : let x is volume of 1st solution and y is the volume of the other one.

now no of moles of HNO₃ in 1st solution = volume of solution × molarity = x × 0.36 = 0.36x

similarly, no of moles of HNO₃ in 2nd solution = volume of solution × molarity = y × 0.15 = 0.15y

so total no of moles in the mixture of them = 0.36x + 0.15y

and volume of mixture = x + y

because no of moles of solute before mixing = no of moles of solute after mixing

⇒ 0.36x + 0.15y = volume of mixture × molarity of mixture

⇒0.36x + 0.15y = (x + y) × 0.24

⇒0.36x + 0.15y = 0.24x + 0.24y

⇒0.12x = 0.09y

⇒4x = 3y

⇒x/y = 3/4

Therefore the volume ratio is 3 : 4.

Answer 2

Explanation:

it's ans is in the ratio of 3/4