Question

In Wheatstone network the resistance in cyclic order are p=10,Q=5 ,s=4 ,R=4 for the bridge to balance

Answer 1

Given In Wheatstone network the resistance in cyclic order are p=10,Q=5 ,s=4 ,R=4 for the bridge to balance

We know that in a balanced Wheatstone bridge or network

 p/q = r/s

10 / 5 = 4/4

 2 = 1 is not balanced so we need to add 5 to q then the circuit will be balanced.

So 5 ohm should be connected in series with q for the bridge to be balanced.

Answer 2

Answer:

I think there must be more than one answers

10 ohm can be connected in parallel with p

and 5 ohm can be connected in series with q