Question

in which case is the number of molecules of water maximum​:
1. 18ml of water
2. 0.18 gm of water
3. 10-³ mol of water
4. 0.00224 L of water vapours at 1 atm and
273 K

Answer 1

The number of molecules are maximum in 0.18 g of water

Answer 2

Answer:

For the 0.18 gm of water maximum molecules of water.

Explanation:

We know that 1 mole of the H2O is 18g and 6.023*10^23 particles and also 22.4 dm^3 or 22.4L.

Thus, 6.023*10^23 will have 22.4L of water so 18mL or 18*10^-3 L of water will have 6.023*10^23 *18*10^-3 / 22.4 which will be 4.84*110^20 particles.

While 18g is having 6.023*10^23 particles then 0.18 g will have 0.18*6.023*10^23/18 which is 0.06*10^23 particles.

While 1 mole is having 6.023*10^23 particles so 10^-3 will have 6.023*10^23*10^-3 which is 6.023*10^20 particles.

Now, 22.4 L will have 6.023*10^23 so 0.0024 L will have 6.023*10^23*0.0024/22.4 which will be 6.56*10^19 particles.

So the maximum is 0.18g of water.