Question

In which case the no: of molecules of water maximum?
1) 18ml water
2) 0.18 g of water
3) 0.0024L of water vapours at 1 atm and 273 K
4) 10-³ mole of water

Answer 1

Answer:

Now, 22.4 L will have 6.023*10^23 so 0.0024 L will have 6.023*10^23*0.0024/22.4 which will be 6.56*10^19 particles. So the maximum is 0.18g of water.

Explanation: