Question

In which chemical reaction does carbon exhibit variation of oxidation state from -4 to +4 ? Write balanced chemical reaction.

Answer 1

Answer:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Explanation:

Oxidation number or oxidation state of an atom in a chemical compound is  the number of electrons lost or gained. It is also defined as the degree of oxidation of the atom in the compound.

This is a theoretical number which can help to decipher the oxidation and reduction in a redox reaction.

Carbon in methane, $CH_4$ is in oxidation state of -4 and in carbon dioxide, $CO_2$, carbon is in oxidation state of +4.

The chemical reaction is:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Answer 2

Answer:

Ch4+202_co2+2h20

Explanation:

Carbon is methane ch4 in oxidation state - 4 & carbon dioxide co2 carbon is in oxidation state+4