Question

in which direction the directional derivative of x^2yz^3 is maximum at (-2,1,-1) and find the magnitude of this maximum.​

Answer 1

Answer:

look at the solution. hope it helps.

Answer 2

Answer:

The correct answer of this question is 4√11

Step-by-step explanation:

Given - Direction the directional derivative of $x^{2} yz^{3}$ is maximum at (-2,1,-1).

Find- Find the magnitude of this maximum.​

So, f = $x^{2} yz^{3}$

Δf =$2xyz^{3}$ | Î + $x^{2} z^{3}$| j^ +$3x^{2} yz^{2} |$ k^

Δf at ( -2 , 1, -1 ) is the

Δf = 4i - 4j + 12k

The maximum in this direction and the value  is = ||Δf||

4√11