Question

In which of the following 2 types of bond lengths are present :
(1) XeF2
(2) CH4
(3) SF6
(4) SF4

Answer 1

Answer:

3)SF6

Explanation:

because there are two type of bond equatorial and axial bond

Answer 2

Answer: 4)SF₄

Explanation:

• SF₄ has sp³d hybridization in which one equatorial position is occupied by a lone pair while two other equatorial positions by bond pair and also the other two bond pairs are at the axial position. So it has two types of bond lengths present in the molecule.

• XeF₂ has three lone pairs and 2 bond pairs, its hybridization is also sp³d but its geometry/shape is linear. Thus, having equal bond lengths.

• CH₄ has sp³ hybridization and tetrahedral shape where all the bond lengths are equal.

• SF₆ has sp³d² hybridization and the molecular geometry of SF₆ is octahedral. All bond lengths are equal in SF₆.