In which of the following case, the degeneracy of orbitals does not exist?
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Answer:
The electronic configuration of Cu
1+
is 1s
2
2s
2
2p
6
3s
2
3p
6
3d
10
4s
0
. The 3d orbital is completely filled, hence it is degenerate. In all other cases, there is one or more than one vacant space in the d orbital which makes it generated.
Explanation:
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