Math, asked by scientificinventions, 4 months ago

In which of the following cases do the two quantities x & y vary

inversely?

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Answers

Answered by motilalchoudhary10

2

Answer:

(A) a + 2b = 3ab

(C) a - 2b = 3ab

(B) 1 + 2ab = 3b

(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab(A) a + 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b

(A) a + 2b = 3ab(C) a - 2b = 3ab(B) 1 + 2ab = 3b(D) 3b + 1 = 2ab

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