Question

in which of the following cases same gas is released 1 Fe+H2SO4 (2) S+HCL (3)Fe+S+HCL (4)Fe S+H2SO4​

Answer 1

Answer:

1)

Explanation:

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Answer 2

Among the given cases, the same gas is released in (3) $\[Fe + S + HCl\]$ and (4) $\[FeS + {H_2}S{O_4}\]$.

Explanation:

• The reaction of $\[Fe + {H_2}S{O_4}\]$ can be given as:

        $\[Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2} \uparrow \]$

• The reaction of $\[S + HCl\]$ does not takes place as sulphur is a non-metal. Non-metals do not react with acids.
• The reaction of $\[Fe + S + HCl\]$ can be given as:

        $\[Fe + S \to FeS\]$

       $\[FeS + 2HCl \to FeC{l_2} + {H_2}S \uparrow \]$

• The reaction of $\[FeS + {H_2}S{O_4}\]$ can be given as:

        $\[FeS + {H_2}S{O_4} \to FeS{O_4} + {H_2}S \uparrow \]$

• Therefore, the same gas ($\[{H_2}S\]$)is released in $\[Fe + S + HCl\]$ and $\[FeS + {H_2}S{O_4}\]$.