Question

In which of the following central atom possesses least oxidation state a) KMnO4 b) K2Cr2O7 c)MnSO4 d) Fe2o3​

Answer 1

Answer:

In mohr salt FeSO

4

⋅(NH

4

)

2

SO

4

⋅6H

2

O, oxidation state of iron is +2 which is least.

K

3

[Fe(OH)

6

] +3+x−6=0 x=+3

K

2

[FeO

4

] +2+x−8=0 x=+6

FeSO

4

⋅(NH

4

)

2

SO

4

⋅6H

2

O +2 state in FeSO

4

(x−2=0)

Fe(CN)

6

3−

x−6=−3 x=+3

Explanation:

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Answer 2

Answer:

The complex having a central atom with least oxidation state is $MnSO_{4}$.

Explanation:

We know that in a neutral complex, all oxidation numbers add up to zero.

In $MnSO_{4}$, the $SO_{4}$ has a -2 charge on it, like $SO_{4}^{-2}$, as it is an ion.

To calculate the oxidation number on $Mn$, we assume:

$Mn$ = x

Now find x,

x + (-2) = 0

x = +2

The oxidation number on $Mn$ is +2.

Conclusion:

$MnSO_{4}$ has a central atom with the least oxidation number.