Question

In which of the following compounds carbon-
chlorine bond distance is minimum :-
(1) CH-1
CH-CH-C1
13YCH,=CHCI
(4) CH=CH-CH-C1​

Answer 1

Answer:

i can not understand your question please write correct question

Answer 2

Answer is option "1"

Explanation:

• A bond between $sp^{3}$ and $sp^{2}$ is stronger than a bond between $sp^{3}$ and $sp^{3}$ because $sp^{2}$ hybridized orbitals contain 33.33% s-character while $sp^{3}$ contains 25% s-character. A general rule, the more s-character in a hybridized orbital, the stronger a bond it will form. Thus a bond between $sp^{3}$ and $sp^{2}$ with 33.33% + 25% % s-character will be more strong than a bond between $sp^{3}$ and $sp^{3}$ with 25% + 25% s-character
• Since $sp^{2}$ carbon bond length is minimum than $sp^{3}$ carbon so, when chlorine gets attached to $sp^{2}$−carbon, the bond length of C−Cl is shorter than the $sp^{3}$ − carbon halogen bond
• Hence, the right answer is option "1"