Chemistry, asked by Shwetas131, 8 months ago

In which of the following dehydration by conc.H2SO4 no rearrangement is favourable?

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Answered by Taniya420

Answer:

Cyclopropyl methanol forms an exceptionally stable carbocation due to the bent p orbitals of carbon. Rest all other options can undergo rearrangement to more stable carbocations since dehydration takes place through E1 mechanism

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In which of the following dehydration by conc.H2SO4 no rearrangement is favourable?​

Answers

In which of the following dehydration by conc.H2SO4 no rearrangement is favourable?