in which of the following equation have X equal 4 y equals to 1 as a solution of of x+3y=7
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Step-by-step explanation:
Graph of the equation 4x+3y−7=0
⇒y=
3
7−4x
When x=−2,y=
3
7−4×−2
=
3
7+8
=5
When x=4,y=
3
7−4×4
=
3
7−16
=−3
x −2 4
y=
3
7−4x
5 −3
Plot the points A(−2,5) and B(4,−3) on the graph and join these points by a straight line AB.The line AB is the graph of the equation 4x+3y−7=
Graph of the equation 2x−3y+1=0
⇒y=
3
2x+1
When x=−2,y=
3
2×−2+1
=
3
−4+1
=−1
When x=4,y=
3
2×4+1
=
3
8+1
=3
x −2 4
y=
3
2x+1
−1 3
Plot the points C(−2,−1) and D(4,3) on the graph and join these points by a straight line CD.The line CD is the graph of the equation 2x−3y+1=0
The lines AB and CD intersect at the point P whose coordinates are (1,1)
The solution is at (1,1)
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