Question

in which of the following equation have X equal 4 y equals to 1 as a solution of of x+3y=7​

Answer 1

Step-by-step explanation:

Graph of the equation 4x+3y−7=0

⇒y=

3

7−4x

When x=−2,y=

3

7−4×−2

=

3

7+8

=5

When x=4,y=

3

7−4×4

=

3

7−16

=−3

x −2 4

y=

3

7−4x

5 −3

Plot the points A(−2,5) and B(4,−3) on the graph and join these points by a straight line AB.The line AB is the graph of the equation 4x+3y−7=

Graph of the equation 2x−3y+1=0

⇒y=

3

2x+1

When x=−2,y=

3

2×−2+1

=

3

−4+1

=−1

When x=4,y=

3

2×4+1

=

3

8+1

=3

x −2 4

y=

3

2x+1

−1 3

Plot the points C(−2,−1) and D(4,3) on the graph and join these points by a straight line CD.The line CD is the graph of the equation 2x−3y+1=0

The lines AB and CD intersect at the point P whose coordinates are (1,1)

The solution is at (1,1)