in which of the following figure OA seems to be the bisector of the angle POQ
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Here OP bisect ∠BOC
∴∠POC=∠BOP …………(i)
and OQ bisect ∠AOC
∴∠AOQ=∠COQ …………….(ii)
and ∠AOB=180 o
[∵AOB is a straight line]
⇒∠BOP+∠DOC+∠COQ+∠AOQ=180 o
⇒∠POC+∠POC+∠COQ+∠CO
=180 o[using (i) & (ii)]
⇒2∠POC+2∠COQ=480 o
⇒2(∠POC+∠COQ)=180 o
⇒2∠POQ=180 o
⇒∠POQ=90 o .
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Explanation:
in first figure oa seems to be bisector of angle poq
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