Math, asked by Balrajsi623, 1 month ago

in which of the following find the number that are divisible by the first number 15,45,504,1230,47322 from brainlyp​

Answers

Answered by Anonymous
0

Answer:

i) 5445

the sum of the odd places 5+4=9

the sum of the even places 4+5=9

9-9=0

since the difference between the sum of the odd places and the sum of even places is 0

it is divisible by 11.

ii) 10824

the sum of the odd places 1+8+4=13

the sum of the even places 0+2=2

13-2=11

since the difference between the sum of the odd places and the sum of even places is 11

it is divisible by 11.

iii) 7138965

the sum of the odd places 7+3+9+5=24

the sum of the even places 1+8+6=15

24-15=9

since the difference between the sum of the odd places and the sum of even places is 19

it is not divisible by 11.

iv) 70169308

the sum of the odd places 7+1+9+0=17

the sum of the even places 0+6+3+8=17

17-17=0

since the difference between the sum of the odd places and the sum of even places is 0

it is divisible by 11.

v) 10000001

the sum of the odd places 1+0+0+0=1

the sum of the even places 0+0+0+1=1

1-1=0

since the difference between the sum of the odd places and the sum of even places is 0

it is divisible by 11.

vi) 901153

the sum of the odd places 9+1+5=15

the sum of the even places 0+1+3=4

15-4=11

since the difference between the sum of the odd places and the sum of even places is 11

it is divisible by 11.

Answered by XxSrishtiRajputxX
0

Answer:

Since the last digit Of the number is 4, it is divisible by 2. On adding all the digits of the number, the sum obtained is 27. Since 27 is divisible by 3, the given number is also divisible by 3. As the number is divisible by both 2 and 3, it is divisible by 6.

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