Question

In which of the following reactions, an

increase in the volume of the container will

favour the formation of products ?

(1) 2NO2(g)
- 2NO(g)
+
O2(g)

(2) H2(g)
+I2(g)
- 2HI(g)

(3) 4NH3(g)
+5O2(g)
-4NO(g)+ 6H2O(l)

(4) 3O2(g)-
2O3(g)

Answer 1

Answer: Option (1) is the correct answer.

Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium at a side that opposes the change.

Therefore, when we increase the volume of a container then it means there will be decrease in pressure. Hence, the reaction will favor side that will have more pressure.

This will lead to increase in number of moles. As a result, a chemical reaction equation that represents formation of more number of moles of products as compared to number of moles in reactants will be the correct equation.

thus, we can conclude that reaction equation $2NO2(g) \rightarrow 2NO(g)+ O2(g)$, is the correct equation.

Answer 2

Answer:

O2(g)+2NO2(g) -> 2NO(g)+O2(g)