Chemistry, asked by shahmehak8285, 9 months ago

In which of the following reactions, H₂O₂ acts as a reducing
agent
(a) PbO₂(s) + H₂O₂ (aq) → PbO(s) + H₂O(????) + O₂ (g)
(b) Na₂SO₃ (aq) + H₂O₂(aq) → Na₂SO₄(aq) + H₂O(????)
(c) 2KI(aq) + H₂O₂ (aq) → 2KOH (aq) + I₂(s)
(d) KNO₂(aq) + H₂O₂ (aq) → KNO₃ (aq) + H₂O(????)

Answers

Answered by classofankur
0

Answer:

a) as reduction means removal of oxygen and only in first reaction pbo2 is reduced to pbo

Answered by brokendreams
2

In reaction b and d H₂O₂ acts as oxidising agent.

Explanation:

  • An oxidising agent is defined as a reagent in a chemical reaction which oxidises another reagent and itself gets reduced in the process.
  • H₂O₂ is the hydrogen peroxide.
  • Oxygen in H₂O₂ has the oxidation number of - 1.
  • In the 1st reaction, we can see that PbO2 is reduced to PbO and peroxide got oxidised to oxygen.
  • In 2nd reaction, we can see that sodium sulphite got oxidized to sodium sulphate and peroxide got reduced to water.
  • In 3rd reaction, its not a redox reaction.
  • In 4th reaction, potassium nitrite is oxidised to potassium nitrate and peroxide is reduced to water.
  • So in 2nd and 4th reaction, peroxide acts as oxidising agent.

For more information about peroxide oxidation,

https://brainly.in/question/5942111

oxidation state of oxygen in peroxide is - Brainly.in

https://brainly.in/question/1631014

The oxidation number of ba in barium peroxide is a) +6 b) +2 c) 1 d) +4 plzzz answer my question fast

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