Question

 In which of the following situations, does the list of numbers involved make as arithmetic progression and why?

(i) The taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km.

(i) The taxi fare after each km when the fare is Rs 15 for the first km and Rs 8 for each additional km.

​

Answer 1

Step-by-step explanation:

Taxi fare for 1 km = 15  

Taxi fare for first 2 kms = 15 + 8 = 23

Taxi fare for first 3 kms = 23 + 8 = 31

Taxi fare for first 4 kms = 31 + 8

Thus, 15, 23, 31, 39 … forms an arithmetic progression, because every next term is 8 more than the preceding term.

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15 + 8 = 23

Taxi fare for first 3 kms = 23 + 8 = 31

Taxi fare for first 4 kms = 31 + 8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. Because every next term is 8 more than the preceding term.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$