Question

In which of the following situations, does the list of numbers involved make an arithmetic progression, and why.
the taxi fare after each km when the fare is ₹15 for the first km and ₹8 for each additional km. ​

Answer 1

Answer:

Fare for first km = Rs. 15

Fare for second km = Rs. 15+8= Rs 23

Fare for third km = Rs. 23+8=31

Here, each subsequent term is obtained by adding a fixed number (8) to the previous term.

Hence, it is in A.P.

Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

Hope this helps you ✌️