In which of the following,the central atom has two line pairs of electrons?(a) sf4 , (b)brf5,(c)so2,(d)xef4
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Answer:
XeF4 has 2 lone pairs.
Explanation:
use hybridization formula,
S+1/2(G-V).
No of atoms other than xe are 4 (i.e s=4).
Group number of xe is 8.
flourine is monvalent since 4 Flourine atoms are present v=4.
so, 4+1/2(8-4)
4+1/2(4)
4+2 = 6 = sp3d2.
since value of 1/2(G-V), is no of lone pairs, we have 2 lone pairs in XeF4.
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