Chemistry, asked by kshiringodara, 6 months ago

In which one of the following neutralization process, the heat of neutralization is different from the other three :-
1. HClO4 + NaOH→ NaClO4 + H2O
2. HNO3 + KOH → KNO3 + H2O
3. CH3COOH + RbOH → CH3COORb + H2O
4. HCl + KOH → KCl + H2O

Answers

Answered by vk2248890gmailcom
6

Answer:

option c is coorect..............

Answered by qwstoke
0

The heat of neutralization is different from the other three is                                     CH₃COOH + RbOH  →  CH₃COORb + H₂O.

  • The heat energy released on the formation of one mole of water from the reaction of one-mole hydrogen ions (H⁺) and one mole of hydroxide ions (OH⁻) is called the heat of neutralization.
  • When a strong acid reacts with a base, the reaction completes.
  • But when a weak acid reacts with a base, the reaction is not completed.
  • Therefore, the reaction between acetic acid and rubidium hydroxide is not a complete neutralization process.
  • Hence, the correct answer is an option (3).
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