Question

In which one of the given reactions a salt is reacting with a base? 1 point a. NaOH+HCl→NaCl+H₂O b. Cu(OH)₂+H₂SO₄→CuSO₄+2H₂O c. KOH+HCl→KCl+H₂O d. 6NH₄OH+Al(SO₄)₃→2Al(OH)₃+3(NH₄)₂SO₄

Answer 1

we have to identify which one of the given reactions , a salt is reacting with a base

a) NaOH + HCl → NaCl + H₂O

b) Cu(OH)₂ + H₂SO₄ → CuSO₄ + 2H₂O

c) KOH + HCl → KCl + H₂O

d) 6NH₄OH + Al(SO₄)₃ → 2Al(OH)₃ + 3(NH₄)₂SO₄

solution : concept : general formula of a base is YOH, where Y is metal and OH is hydroxide ion.

so, NaOH , KOH and NH₄OH, Cu(OH)₂ are base.

HCl , H₂SO₄ are acid.

now let's see the reaction.

a. NaOH (base) + HCl (acid) ⇒NaCl (salt) + water

b. Cu(OH)₂ (base) + H₂SO₄ (acid) ⇒ CuSO₄ (salt) + water

c. KOH (base) + HCl (acid) ⇒ KCl (salt) + water

d. NH₄OH (base ) + Al(SO₄)₃ (salt) ⇒2Al(OH)₃ (base) + 3(NH₄)₂SO₄ (salt)

Therefore option (d) is the reaction of a salt with a base.

Answer 2

Answer:

we have to identify which one of the given reactions , a salt is reacting with a base

a) NaOH + HCl → NaCl + H₂O

b) Cu(OH)₂ + H₂SO₄ → CuSO₄ + 2H₂O

c) KOH + HCl → KCl + H₂O

d) 6NH₄OH + Al(SO₄)₃ → 2Al(OH)₃ + 3(NH₄)₂SO₄

solution : concept : general formula of a base is YOH, where Y is metal and OH is hydroxide ion.

so, NaOH , KOH and NH₄OH, Cu(OH)₂ are base.

HCl , H₂SO₄ are acid.

now let's see the reaction.

a. NaOH (base) + HCl (acid) ⇒NaCl (salt) + water

b. Cu(OH)₂ (base) + H₂SO₄ (acid) ⇒ CuSO₄ (salt) + water

c. KOH (base) + HCl (acid) ⇒ KCl (salt) + water

d. NH₄OH (base ) + Al(SO₄)₃ (salt) ⇒2Al(OH)₃ (base) + 3(NH₄)₂SO₄ (salt)

Therefore option (d) is the reaction of a salt with a base.