Question

In which phase or on which axis are -8, 2) [6, -3), -8, 0), (6, 2) and -k, -3) Hindus. Of your jawans
Display the verification points in the yam-plane.​

Answer 1

Step-by-step explanation:

Since, 2z1/3z2 = k'i ...(Given)

or, z1/z2= (3k'/2) i

or, z1/z2= ki (where 3k'/2=k) ...(1)

|(z1-z2)/ (z1+z2)| = |z1{1-(z2/z1)}/z1{1+(z2/z

Cancelling z1's, above equation becomes

|(z1-z2)/ (z1+z2)| = |[1-(z2/z1)]/[1+(z2/z1)]|

= | (1-ki)/ (1+ki) | ...(using (1))

= |(1-ki)|/ |(1+ki)|

= 1

Answer 2

the answer will be 1.

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