Question

In which point the line x+2y-1=0 cut x axis
(1,0)
(0,1)
(2,0)
(0,2)​

Answer 1

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Asked on December 30, 2019 by

Ruchita Garg

A straight line l

1

with equation x−2y+10=0 meets the circle with equation x

2

+y

2

=100 at B in the first quadrant. A line through B, perpendicular to l

1

cuts y-axis at P(0,t). The value of 't' is

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ANSWER

equation of l

1

: x−2y+10=0

equation of l

1

: y=

2

1

x+5

Slope of l

1

=

2

1

Since l

2

is perpendicular to l

1

thus,

Slope of l

2

=−2

Equation of l

2

,y=−2(x−10)

⇒y+2x=20

Hence, t=20