Math, asked by rinku15092006, 3 months ago

In which quadrant are on which axis do each of the point (-2,4) (3,-1) (-1,0) (-3,-5) (1,2)​

Answers

Answered by Anonymous
2

Answer࿐

Find two consecutive odd numbers such that two fifths of the smaller number exceeds two ninths of the larger by 4

Solution :

Let one odd number be ' 2n + 1 '

This is smallest odd number .

Other consecutive odd number be ' 2n + 3 '

This is largest odd number .

A/c , " Two fifths of the smaller number exceeds two ninths of the larger by 4 "

First consecutive smallest odd number :

= 2n + 1

= 2(12) + 1

= 24 + 1

= 25

Second consecutive largest odd number :

= 2n + 3

= 2(12) + 3

= 24 + 3

= 27

Alternative : You may solve this question by taking ' x ' as smallest consecutive odd number and ' x + 2 ' as biggest consecutive odd number .

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Answered by Anonymous
2

Answer:

Quadrant (I) :

(1, 2)

Quadratic (II) :

(-2, 4)

Quadrant (III):

(-3, -5)

Quadrant (IV):

(3, -1)

X' axis: ( negative X axis )

(-1, 0)

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