In which quadrant do the following points lie (4,-2),(-2,-5),(4,2), (-3,5) 25) find the area of a traingle ,two sides of which are 14cm and 12cm amd the perimeter is 42 cm ?
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2
Answer:
Step-by-step explanation:
See fig for qudrants
II part
third side
=perimeter-(12+14)
=42-26
=16
s=(a+b+c)/2=42/2=21
So are S= √21(21-12)(21-14)(21-16)
=√21*9*7*5
=√3*7*3*3*7*5
=(3*7) √15
area=21√15 cm²
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Answer:
A = 21 √15.
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