Question

In which quadrant do the following points lie (4,-2),(-2,-5),(4,2), (-3,5) 25) find the area of a traingle ,two sides of which are 14cm and 12cm amd the perimeter is 42 cm ?​

Answer 1

Answer:

Step-by-step explanation:

See fig for qudrants

II part

third side

=perimeter-(12+14)

=42-26

=16

s=(a+b+c)/2=42/2=21

So are S= √21(21-12)(21-14)(21-16)

=√21*9*7*5

=√3*7*3*3*7*5

=(3*7) √15

area=21√15 cm²

Answer 2

Answer:

A = 21 √15.

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