Question

in which quadrant does the following lie :-) (1-√2,1+√2) (-3+√5,-3√5) (2-√3,2+√3)​

Answer 1

Answer:

1 . 1st quadrant

2. 3rd quadrant

3. 1st quadrant

Answer 2

Step-by-step explanation:

$since \: \sqrt{2 } > 1 \: so \: 1 - \sqrt{2} < 0 \: and \: 1 + \sqrt{2} > 0 \\ that \: is \: (1 - \sqrt{2} ,1 + \sqrt{2} ) \: lies \: in \: 2nd \: quadrant \\ since \: \sqrt{5} < 3 \: so \: - 3 + \sqrt{5} < 0 \: and \: - 3 \sqrt{5} < 0 \\ that \: is \: ( - 3 + \sqrt{5} , - 3 \sqrt{5} ) \: lies \: in \: 3rd \: quadrant \\since \: \sqrt{3 } < 2\: so \: 2- \sqrt{3} > 0 \: and \: 2 + \sqrt{3} > 0 \\ that \: is \: (2 - \sqrt{3} ,2 + \sqrt{3} ) \: lies \: in \: 1st\: quadrant$